CHEM 121L General
Chemistry Laboratory Revision 2.0 Distillation of Alcohol To learn about the separation of substances.· To learn about the separation technique of
distillation.· To learn how to characterize a substance
using its density.· To learn about fermentation.· In this laboratory
exercise, we will distill a ferment to boost its Alcohol content. For the
present case, our ferment will be a sample of a commercially produced wine of
about 10-12% Alcohol and the resulting distillate will be a crude form of
brandy. We will characterize the resulting Brandy by its density, its
combustibility and its boiling point. The density measurement will allow us to
determine the Volume Percentage Alcohol in the Brandy, which will in turn allow
us to determine its Proof. The simple distillation process we will employ
typically produces a Brandy of approximately 120-140 Proof. Alcohols are
important industrially and commercially. Principally important commercial
alcohols include Methanol, Ethanol, Isopropanol and Ethylene Glycol. Ethanol,
or Ethyl Alcohol, is used as a solvent, fuel additive, and in lotions,
tinctures and medicines. It is probably most familiar as the alcohol of
alcoholic beverages and is referred to generically as Alcohol, Common Alcohol
or Grain Alcohol. For this last purpose, Ethanol (CH3CH2OH; or EtOH for short)
is produced by fermentation of sugars. Fermentation alone does not produce
beverages with an Alcohol content greater than 12 to 15% because the fermenting
yeast is destroyed at high Alcohol concentrations. To produce beverages of
higher Alcohol content the aqueous ferment must be distilled. The fermentation
of carbohydrates into Alcohol is one of the oldest known chemical processes.
Fermentation can be represented as: Sugar Alcohol + Carbon Dioxide (Eq. 1) The
reaction is catalyzed by yeast enzymes called zymases. A balanced chemical
reaction for this process, assuming the sugar is Table Sugar or Sucrose, is:
C12H22O11 + H2O 4 CH3CH2OH + 4 CO2 (Eq. 2) The fermentation process is started
by mixing a source of sugar, water and yeast and allowing the yeast to act in
an oxygen free environment. This anaerobic environment forces the yeast to shut
down the “burning” of sugar and allows them to instead ferment Alcohol. P a g e
| 2 Commercially, fermentation is the first step in the production of wine,
beer, mead and cider.
http://www.askmen.com/fine_living/wine_dine_archive_300/376_10-wines-shell-swoon-for.html
Nejmlez, CC BY-SA 3.0, https://commons.wikimedia.org/w/index.php?curid=295522
The Alcohol produced by this fermentation process can be concentrated from the
aqueous solution in which the fermentation takes place by distillation.
Distillation is a separation process for a mixture of liquids or oils. It
relies on differences in the boiling points of the component liquids to be
separated. The mixture to be separated is added to a Distilling Pot where it is
heated to the boiling point. Lower boiling components will preferentially
vaporize first. The resulting vapor passes into a Distilling Head and then into
a P a g e | 3 Condensor. Within the Condensor the vapor is cooled and it
liquifies. The resulting liquid is then collected in a Receiving Flask.
Initially, low boiling components are collected in the Receiving Flask. As the
distillation proceeds, these components are depleted from the Distilling Pot
and higher boiling components begin to distill over. Switching out the
Receiving Flask at the appropriate point allows for the separation of the
component liquids of the mixture. The particular type of distillation we will
be employing in this laboratory is known as Simple Distillation. Simple
distillation works particularly well on mixtures of two liquids which have a
very large boiling point difference. The lower boiling component distills off
first and can be collected. The higher boiling component then follows. A
downside of simple distillation is that the purity of the distillate is rarely
100%. This is because the distillation vapor is only enriched in the lower
boiling component. Some of the higher boiling component will be present as
well. So the condensed distillate will be a mixture enriched in the lower
boiling component, but still containing some of the higher boiling component.
To make matters worse, as the distillation proceeds, the liquid in the
distilling pot will have a greater, and greater percentage of higher boiling
component. Hence, the distillate, over time, will wind-up containing more, and
more of the higher boiling component. Mixtures of a large number of similarly boiling
liquids can be separated by a technique called Fractional Distillation. In
fractional distillation, a fractionating column allows the vapor arising from
the distillation pot to be repeatedly recondensed and revaporized. After a
number of these recondensation/revaporization steps, the lower boiling
component will be relatively free of any higher boiling components. This allows
for a more thorough separation of the liquids. This P a g e | 4 method of
distillation is employed to separate the hydrocarbon components of Crude Oil as
a part of the Refining process. Medium Heavy Crude Oil Gasoline (Key
Hydrocarbon Component of Crude Oil) Distillation of Alcohol from an
Alcohol/Water ferment is the second major step in producing Liquor. The source
of the fermentation sugar helps define the type of liquor to be produced.
Liquor Sugar Source Brandy Grapes, Apple, Pear Whisky Barley, Rye, Wheat, Corn
Gin Grapes, Sugar Beets, Sugarcane Vodka Potato, Grain Rum Molasses Tequila
Agave Whisky Still https://en.wikipedia.org/wiki/Distilled_beverage 19th
Century Bourbon By Gettysburg National Military Park, GETT 31373
-http://www.cr.nps.gov/museum/treasures /html/B/gett31373.htm, Public Domain,
https://commons.wikimedia.org/w/index.php?curid=336178 P a g e | 5 Ethyl Alcohol
has a boiling point of 78.5oC and that of Water is 100oC. Hence, initially a
simple distillation will be relatively efficient in enriching Alcohol. But,
because the simple distillation process is not 100 % efficient, we will have to
determine the Alcohol content of our distillate. This can be done by measuring
its density, which as we have seen previously depends heavily on the
composition of the system. The density of a substance, be it a pure substance
or a mixture, is given by: density = mass volume (Eq. 3) We can compare our
distillate's density with tabulated values of the density of known mixtures of
Alcohol and Water to determine its Alcohol content; typically reported as the
Volume Percentage Alcohol. Most manufacturers of liquor report the Alcohol content
by its Proof. In the US system, the Proof is double the Vol. Percentage
Alcohol: Proof = 2 x Volume Percentage (Eq. 4) Historically, the term Proof
derives from a method of measuring the Alcohol content of liquors which
“proved” they were not diluted. If gunpowder mixed with liquor would still
ignite after the Alcohol burnt off, then the Alcohol was not considered to be
diluted. The minimum Vol. Percentage Alcohol required for ignition is 57%;
which, historically, was assigned a value of 100 degrees Proof. Levels of
Alcohol in liquor are still measured by Proof, for tax purposes, but the scale
is different in different countries. In addition to the distillate’s density,
we will also test the quality of our distillate by combustion. Mixtures high in
Alcohol content will readily combust, producing a light blue color flame. Those
that are high in water content will not combust at all. Finally, noting the
boiling temperature of our distillate also gives us a qualitative feel for its
composition. The closer the boiling temperature is to 100oC, the boiling point
of Water, the less Alcohol it contains. We will distill a Carlo Rossi red wine
of Alcohol content 10-12%, collecting the distillate in fractions of about 15
mL each. We will measure the density of the first fraction only, which we
expect to be the most enriched in Alcohol, to determine its Alcohol content or
Proof. This, and subsequent fractions, will also be tested for combustibility.
And, the temperature at which each distillate is collected will be noted; a
final qualitative measure of the composition of the distillate. P a g e | 6
Pre-Lab Safety Questions 1. Do a short internet search for an NFPA 704 Fire
Diamond for Ethanol. What is the Degree of Hazard for Ethanol's flammability?
What does this rating mean? 2. What is the definition of the flashpoint for a
substance? Specifically, what is the flashpoint for pure Ethanol? 3. Why are
Steam burns more damaging than those of boiling Water? P a g e | 7 Procedure
Our distillation apparatuses have been used over the years for distilling a
number of different organic compounds, some of which are toxic. Under no
circumstances should you drink the Alcohol produced by this distillation. The
product is not a beverage quality Alcohol. 1. Obtain a distillation apparatus
as pictured below. Use a small Bunsen burner flame as the heat source. Be sure
the distillation apparatus is thoroughly clean. Use a 500 mL RoundBottom flask
as a distilling pot. Use a 25 mL Round-Bottom flask as a receiver.
http://en.wikipedia.org/wiki/File:Simple_distillation_apparatus.svg 2. Obtain a
sample of wine from your laboratory instructor. Your instructor will add the
wine directly to your 500 mL distilling flask. The flask should be ¼ to ½ full.
(You are not allowed to obtain this sample yourself.) 3. Add a few boiling
chips to the ferment. Set-up the distillation apparatus. (You must have your
apparatus inspected by your lab instructor.) Now, heat slowly to maintain a
steady distillation rate. 4. Collect four distillate fractions, of about 15 mL
each. Note the temperature range, the beginning and ending temperature, over
which each distillate is collected. As each fraction is collected, place the
distillate into a large, stoppered test tube. P a g e | 8 5. Determine the
density of the distillate (Only done for the first fraction.): a) Pre-weigh a
25 mL Erlenmeyer flask with stopper. b) Using a volumetric pipet, transfer 5 mL
of distillate into the 25 mL Erlenmeyer flask. c) Weigh the flask plus
distillate. Determine the density of the first distillate fraction. 6. Place
approximately half a milliliter of each distillate fraction onto a watch glass.
Try lighting it with a match. Note the color and quality of the flame. 7. You
may want to determine the Proof of your fraction #1 distillate before you leave
the lab. Tabulated density data for aqueous Alcohol solutions is available
below; see step 4 of the Data Analysis. A crude computer program to carry-out a
Lagrange Interpolation of this data is available on the laptop computers in the
laboratory. P a g e | 9 Data Analysis 1. Calculate the Density of Fraction #1
of the Distillate. 2. Comment on the Combustibility of each Fraction of the
Distillate. 3. Comment of the Boiling Point of each Fraction of the Distillate.
4. Use the data below to determine the Percentage by Volume Alcohol content for
Fraction #1 of the Distillate. Interpolate as needed. Report this result. % by
Volume Density [g/ml] 0.00 0.99908 5.00 0.99190 10.00 0.98569 15.00 0.98024
20.00 0.97518 25.00 0.97008 30.00 0.96452 35.00 0.95821 40.00 0.95097 45.00
0.94277 50.00 0.9335 55.00 0.9235 60.00 0.9128 65.00 0.9013 70.00 0.8892 75.00
0.8765 80.00 0.8631 85.00 0.8488 90.00 0.8331 95.00 0.8153 100.00 0.7932 5.
Determine the Proof of Fraction #1 of the Distillate. You must do this using a
Lagrange Interpolation method on a subset of this data set. A crude program to
do this will be available on the computers in the Lavender Lounge. P a g e | 10
Post Lab Questions 1. The boiling points of heptane and octane, two components
of petroleum, are 98.42oC and 125.66oC respectively. Would Simple Distillation
be an effective method for completely separating a mixture of these two
hydrocarbons? Explain. 2. Would it be worth our time to calibrate the 5 mL
pipette we used in Procedure step 5 (c) when measuring the density of our first
distillate fraction? Explain. 3. What is the highest proof to which an aqueous
Alcohol solution be boosted to using distillation? (You may need to use
external sources.) 4. What is the boiling point of the alcohol Methanol? How is
Methanol typically removed from Moonshine? P a g e | 11 Appendix -
Interpolation Interpolation is a method whereby a new data point is generated
from a set of data points that are already tabulated. How do we best perform an
interpolation? We will illustrate two methods for interpolating tabulated data
in the following examples. Suppose we have a series of solutions of Fuming
Sulfuric Acid, Sulfuric Acid (H2SO4) infused with Sulfur Trioxide (SO3), for
which the density has been measured. Fuming Sulfuric Acid % H2SO4 Density
[g/mL] 100 1.839 95 1.862 90 1.880 85 1.899 80 1.915 75 1.934 70 1.952 Now
suppose we have measured the density of a Fuming Sulfuric Acid solution whose
composition is not known. Take this measurement to be 1.887 g/mL. From the
tabulated results we can see the composition of the mixture is between 85 and
90% Sulfuric Acid. Interpolation will allow us to hone in on a prediction of
the composition that is more accurate by generating a new data point between
these two compositions. If the data is perfectly linear, interpolation is
particularly easy. A simple plot of this data shows it to indeed be linear.
Linear interpolation can be illustrated rather easily: P a g e | 12 We simply
determine how much the slope of the line moves us from y1 up the y-axis over an
increment of (xm – x1). Then, the new data point ym, based on our measurement
xm, can be determined via: ym = y1 + [(y2 – y1)/(x2 – x1)] (xm – x1) For our
Fuming Sulfuring Acid example, we have: ym = 90 + [(85 – 90)/(1.899 – 1.880)]
(1.887 – 1.880) = 88.15 Unfortunately, much data exhibits significant
curvature. In this case a polynomial fit to the data might be more appropriate.
And, more than two tabulated data points will be required for the
interpolation. Afterall, n data points are required to define a polynomial of
degree n – 1. Consider the density of Water as a function of temperature: Temp.
(oC) Density (g/mL) 0 0.99987 10 0.99973 20 0.99823 30 0.99567 40 0.99224 50
0.98807 60 0.98324 70 0.97781 80 0.97183 90 0.96534 100 0.95838 A quick plot of
this data illustrates its curvature. This is particularly true at lower
temperatures. P a g e | 13 So, if we attempt to use a linear interpolation
scheme to determine the density of Water at say 15 oC from the Tabulated
densities at 10oC and 20oC, we obtain the following result: ym = 0.99973 +
[(0.99823 - 0.99973)/(20-10)] (15 - 10) = 0.99868 g/mL Experimentally, the
density of Water at 15 oC is found to be 0.99913 g/mL. The interpolated value
is in error by 0.045%. Another interpolation method, that of Lagrange, takes
into account changes in the slope between neighboring pairs of points and
therefore accounts for, to some degree, curvature in the data. Using this
method, and data at 10oC, 20oC and 30oC, results in a better interpolated
result of 0.99898 g/mL. The error has now been reduced to 0.015%. The
interpolation method of Lagrange is encoded in a number of software packages. A
simple DOS program encoding this algorithm is available on the computer in the
Lavender Lounge of Jones Hall.

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